records, EVP_EncodeUpdate() may misbehave. This happens when there's
a record boundary between the two ending b64 equal signs, which makes
EVP_EncodeUpdate think there has been more than one EOF, and therefore
add an extra NUL at the end of the output buffer. This fix corrects
that problem.
/* If we are at the end of input and it looks like a
* line, process it. */
if (((i+1) == inl) && (((n&3) == 0) || eof))
+ {
v=B64_EOF;
+ /* In case things were given us in really small
+ records (so two '=' were given in separate
+ updates), eof may contain the incorrect number
+ of ending bytes to skip, so let's redo the count */
+ eof = 0;
+ if (d[n-1] == '=') eof++;
+ if (d[n-2] == '=') eof++;
+ /* There will never be more than two '=' */
+ }
if ((v == B64_EOF) || (n >= 64))
{